encode PHP

[JmZ]

He said he wanted to convert a given string to the '\x[0-9a-f]{2}' form (which javascript uses, not PHP), which is what both you and I gave working functions for.

As mentioned in my previous post, I was merely giving an example of an alternative, more modern way you could do it using PHP 5.3. I never stated it was the best way in terms of portability.

Every developer knows what language uses the '\x' representation, which is why my assumptions were made. In which case, what I said about needing one occurrence per character remains true. You can also see this from his initial example where he uses it on a per-character basis, implying it is a javascript string or similar.

Have a good day Lock Down, don't be so defensive in future, remember it was just a response.

[Lock Down]

My bad then as I thought he mentioned php.
So I think you should give him the exact code needed to convert it with javascript.

[JmZ]

It seems like he wanted a PHP solution to the problem, just the string he's trying to convert to appears to be a javascript string.

What does it matter though, he has the answer now, twice lol.

[Lock Down]

Where was the twice.

Your function with no reference to the rest of the code posted was not an answer and you should really finish what you start.

Let's see the the javascript answer to the question. I am sure he could use it as other members.

Shouldn't take you but a few minutes for a working tested solution.

[JmZ]

I didn't feel the need to reference the rest of the code as you had already posted it previously, this was simply a potential replacement for the function in that code. Since there was only one function in use, it seemed obvious to me that would be the one to replace. I did finish, thanks to the rest of the code already existing due to your post.

As for the javascript, he asked for it in PHP, not JS. But for your satisfaction:

var str = 'some string';
str = str.replace(/./g, function(c) { return '\\x' + c.charCodeAt(0).toString(16); });
// str now contains the characters using '\x' notation

However, it won't evaluate the characters. This is due to the '\\x' being evaluated first in the return statement, then the character code (in hex) separately. Meaning the string will literally contain the '\x' notation.

Doing something like the following would result in the '\x' codes being evaluated, leading to the initial string.

str = str.replace(/./g, function(c) { eval("c = '\\x" + c.charCodeAt(0).toString(16) + "';"); return c; });

As for it being tested, there's no need, I know it works from reading the code.

[Lock Down]