[JAVA} Need help in a Nested Loop

[conrey]

need help in this output please..

12345
22345
33345
44445
55555

[Gaurav]

/**
 * Prints the pattern in the post above.
 * 
 * @author Gaurav
 * @version 1.0
 */
public class pattern
{
    public static void main(String[] args) {
        for(int i = 1; i <= 5; i++){
            for(int j = 1; j <=5; j++){
                if(j < i){
                    System.out.print(i);
                }
                else{
                    System.out.print(j);
                }
            }
            System.out.println();
        }
    }
}

That should do it .

One suggestion. Please do try doing the programs yourself first.. If you're stuck somewhere then only look out for help. Just typing in the pattern and asking for the solution gives the impression that you want us to do your homework (not saying that this might be the case). But I and many others would appreciate if you post your progress as well along with the question.

[conrey]

nope I'm self learning bro, and I really make one for this but the problem is I didn't really think putting if-else in a nested for loop..

[conrey]

any can help me out ive been trying so hard but failed..

Output:
54321
4321
321
21
1

But using the "while" syntax. not nested for loop. is it possible?

[Gaurav]

Here you go:

/**
 * Prints the above mentioned pattern
 * 
 * @author Gaurav <Gaurav@besthostingforums.com>
 * @version 1.0
 */
public class PatternKWWH
{
    public void display() {
        int n = 5;        
        while(n >= 1){
            int k = n;
            while(k >= 1){
                System.out.print(k);
                k--;
            }
            System.out.println();
            n--;
        }
        
    }
}

[conrey]

^ Thank you so much gaurav its perfect.. well I have a new problem bro our professor said "Make a nested loop, that will prints out All Even numbers in in 1-50, and when it goes to 51-100 it prints out odd numbers"
basically when its still 1<50 it will prints out 2,4,6,8..50 and when its 51-100 it prints out 51,53,55,57,59..99..

Ive tried this so far..

public class oddeven {

    public static void main(String[] args){
    	System.out.println("Even numbers: ");
    	for(int a=1;a<=50;a++){
    		if(a%2 == 0){
    			System.out.println(a);
    		}
    	}
    	System.out.println("Odd numbers: ");
    	for(int a=51;a<=100;a++){
    		if(a%2 == 1){
    			System.out.println(a);
    		}
    	}
    }


}

but our processor says make it into a single loop now I can't do it.. please please help.

[ajinkya9]

^^
Make 1 loop, go from 0 to 100.
In there put an if clause.
So,

if a<50:
    if a%2 == 0:
        print a
else:
    if a%2 == 1:
        print a

I think you have no idea what you're doing and just wasting time.
It can't get easier than this, and you're struggling to complete them.
So do some reading and get your head around this stuff. Start from the basics. Read your textbook and make sure you understand each word. Use a dictionary if English is not your First Language.

[dr5hn]

System.out.println("Odd numbers: "); for(int a=51;a<=100;a++){ if(a%2 == 1){ System.out.println(a);

You Getting Wrong Here Make it 0 instead of 1

[Gaurav]

He wants to print odd numbers.. so the remainder after dividing by 2 should be one.. He's correct there..

Try this:

/**
 * Prints the above mentioned pattern
 * 
 * @author Gaurav <Gaurav@besthostingforums.com>
 * @version 1.0
 */
public class oddeven
{
     public static void main(String[] args){
    	for(int i = 1; i <= 100; i++) {
            if(i <= 50 && i % 2 == 0) {
                System.out.println(i);
            }
            else if(i > 50 && i % 2 == 1){
                System.out.println(i);
            }
        }
    }
}