JQuery and RegExr Help :|

[Porsche_maniak]

Hi guys.
I have really big difficulties of doing the following so any help would be appreciated.

Here's my stack

$(document).test(1000).mouseover(function(){
alert(1); alert(2);
});

$(document).inbetween();
$(document).test(2000).mouseover(function(){alert(1); alert(2);});

Ok so i want to take the functions(that are bold) with regexr that contain test() function attached. It must work in all major browsers + IE6.

I have the following pattern but can't do it good enough to work.
\$\(.*\)\.test\(\d*\)\.(?:\r|\n|.)+\);(?:\$)+

Thanks

EDIT: Ok i found the proper pattern guys. It's :
\$\(.*\)\.test\(\d*\)\.[^\$]*

Porsche_maniak Reviewed by Porsche_maniak on 31st May 2012. JQuery and RegExr Help :| Hi guys. I have really big difficulties of doing the following so any help would be appreciated. Here's my stack $(document).test(1000).mouseover(function(){ alert(1); alert(2); }); $(document).inbetween(); Rating: 5

[deliteblogger]

well regarding the pattern, I don't really see why (?:\$)+ is at the end, it means 'at least one dollar sign after the ;' and maybe you need to make the '.' non-greedy by adding question marks: \$\(.*?\)\.test\(\d*\)\.(?:\r|\n|.)+?\);

[Porsche_maniak]

Yes i know that (?:\$)+ is not correct. But i think thats the only way delimiter for the next match.. or maybe you are close ?
The thing is that if i have a function or something that ends with ); inside the mouseover function the regex doesn't work as expected.Your pattern matches till the first occurance of );
but it should be to the last. How to do this?

[deliteblogger]

Yes you're right... I think for this you need to match nested parentheses and such, and Regular expression is not the best tool for that.

http://stackoverflow.com/questions/1...ested-patterns

[Porsche_maniak]

@deliteblogger thanks for you help