Php replacing characters !

[softleaks]

hi my database has text with characters like this : "%28" , "%29"

i guess they are coming instead of the curly braces : "(" , ")"


i just want to filter these things out.

"str_replace" function is not working for this characters.

can somebody give me an alternate method in doing this ???

thanks.

softleaks Reviewed by softleaks on 30th May 2011. Php replacing characters ! hi my database has text with characters like this : "%28" , "%29" i guess they are coming instead of the curly braces : "(" , ")" i just want to filter these things out. "str_replace" function is not working for this characters. can somebody give me an alternate method in doing this ??? Rating: 5

[CJ]

major problem here is, i cant understand what u want. Otherwise str_replace works fine if u need to replace some text

[softleaks]

i tried with str_replace. It is not working.

this is my code :

$a="%282009%29";
str_replace("%28","",$a);

[deAthbLisS]

if you are fetching the data from the database and its coming like %28 , %29
you can use htmlspecialchars_decode
more: http://www.php.net/manual/en/functio...ars-decode.php

or try using the strip_tags

[CJ]

i tried with str_replace. It is not working.

this is my code :

$a="%282009%29";
str_replace("%28","",$a);

have u tried
str_replace("(","",$a) ?

maybe, it is saved in html encoded format in DB & retrieved as proper character

[softleaks]

@humour

i tried that too.

nothing happened.

@deAthbLisS

i tried the htmlspecialchars and it is not working.

trying strip_tags now....

[CJ]

i guess u forgot to assign the value of replace function back to variable

$a="%282009%29";
$a=str_replace("%28","",$a);

?

[JmZ]

Yeah its not working because str_replace returns, it doesn't change by reference.

you need to assign it to a variable.

Also see urldecode().

[Putin]

^agree with JmZ. need urldecode() but if you want to use str_replace for them (if you're fussy) use this:

$str = "%29 lolcat %28";
echo str_replace(array("%29","%28"), array("\)","\("), $str);

should do the trick.