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31st Aug 2011, 12:48 PM #1OPMember
Looking for php coder - small job.
Hello guys,
I currently have this (http://codecanyon.net/item/simple-we...comments/46483) script on dynamic pages of my site.
It gives the user 2 input fields, name and comment box.
Also it has gravatar support (as avatar).
What I need doing, is since we are running;
PHP Code:(mysql_query('select id,username,password,email,avatar from users where username="'.$_SESSION['username'].'"'));
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The script is one file.
If your interested let me know.
Cheers,
Ryanvps9Ryan Reviewed by vps9Ryan on . Looking for php coder - small job. Hello guys, I currently have this (http://codecanyon.net/item/simple-website-comments/46483) script on dynamic pages of my site. It gives the user 2 input fields, name and comment box. Also it has gravatar support (as avatar). What I need doing, is since we are running; Rating: 5
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31st Aug 2011, 02:17 PM #2MemberWebsite's:
tehMoviez.com 0Senes.com GeekFaceGames.comi think your description is not clear
JokerHacker Blog
JokerHacker PHP coding Service // back again!
CurlAxel PHP Download Accelerator
hardly remembering the milk :p
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31st Aug 2011, 02:21 PM #3OPMember
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31st Aug 2011, 02:23 PM #4Respected MemberWebsite's:
DL4Everything.com Soft2050.in
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31st Aug 2011, 02:24 PM #5OPMember
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31st Aug 2011, 02:40 PM #6MemberWebsite's:
tehMoviez.com 0Senes.com GeekFaceGames.comit's difficult to help you without having a idea about your code and your DB, exposing them publicly is dangerous too, so pm a dev here and he should help you
JokerHacker Blog
JokerHacker PHP coding Service // back again!
CurlAxel PHP Download Accelerator
hardly remembering the milk :p
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31st Aug 2011, 02:48 PM #7MemberWebsite's:
hoangthienlong.vnI want to help you but I don't understand what you want of your post, can by my English not good.
Your mean is you want get avatar from db after use submit name? Same bellow
Code:$username = mysql_real_escape_string($_POST['username']); $avatar = ""; $q = mysql_query("SELECT id,username,password,email,avatar FROM users WHERE username='$username' LIMIT 1"); $t = mysql_num_rows($q); if ($t == 1) { $r = mysql_fetch_array($q); $avatar = $r['avatar']; }
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31st Aug 2011, 05:53 PM #8MemberWebsite's:
vaporhostn.comCode:$SQL = mysql_query("SELECT * users WHERE Table='something'"); echo mysql_error(); while ($db_field = mysql_fetch_assoc($SQL)) { $name = $db_field['name']; $avatar = $db_field['avatar']; echo "$name $avatar";
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31st Aug 2011, 08:17 PM #9OPMember
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31st Aug 2011, 10:59 PM #10MemberWebsite's:
vaporhostn.com
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