Can you solve this puzzle ?

[cvrle77]

Prisoner A sees 2 white hats
Prisoner B sees 1 white 1 black
Prisoner C sees 1 white 1 black

or

Prisoner A sees 2 white hats
Prisoner B sees 2 white hats
Prisoner C sees 2 white hats

3 white hats, 2 black
2 white hats on head / leaves 1 white and 2 black in the game
(trying to solve)

In case where someone sees black/white hats on opposite sides (B and C see black white), they're not able to solve the answer, because there could be any color on their head. Also, 2 persons could guess. This option is self excluding for persons B and C
In case where someone sees white/white combination, there's still one white left and 2 black, as possibility. Therefore, also unable to solve it. 3 persons have equal chance in solving it, since they all see the same, and can think the same.
Since solution MUST have an answer, the only way is that persons B and C see white/black combination, where A person is the person with black hat.

cvrle77 Reviewed by cvrle77 on 3rd Oct 2012. Can you solve this puzzle ? Good evening, ladies and gentlemen. We are tonight's entertainment, i only have one question: "how did he solve the puzzle ??" First the rules: No google, no youtube, bing :P or what soever. This puzzle doesn't need any sort of knowledge about probabilities or mathematics, it is only about LOGIC, and that's why i love it so much, just think logically and be patient, the answer is quite tricky. The puzzle: We have 3 prisoners, and there is a decision about letting one of them go free, Rating: 5

[ilyacine]

Now we're talking !

In case where someone sees black/white hats on opposite sides (B and C see black white), they're not able to solve the answer, because there could be any color on their head. Also, 2 persons could guess. This option is self excluding for persons B and C

Actually this is a factor key, because there is a way to know what's on your head if you see Black & White on B&C.
Also i can see that you're trying to solve this by using probability laws, and there is no way/solution for it using this method (Obviously they all have the same chance/probability of having a white or black hat if they see a 2 whites).
The trick is to assume you are one of them (let's say you're the winner) how could you guess your color is totally depending on why the 2 others couldn't guess theirs.